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All Numbers Are Equal 1 j; ~% X: a$ t8 n
Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then
( V8 W6 y" _* u. y+ b7 i/ H8 j i% m, R0 f/ F9 D
a + b = t0 c6 S' w" z% l! y i
(a + b)(a - b) = t(a - b), @! ?2 l4 Q: m! d1 q6 J! d6 Y' c
a^2 - b^2 = ta - tb
" E" v F2 U$ l# }) ~& T' E% @. h: |2 a; Na^2 - ta = b^2 - tb
/ b" f/ @9 N) K# o7 v) la^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
* }0 V, ^7 F2 q7 i6 A6 k/ Q(a - t/2)^2 = (b - t/2)^2
3 Z1 z$ c$ o+ x0 b2 Fa - t/2 = b - t/2
/ O3 g; y" Y, k7 q: c) g' w5 R5 F/ Ma = b
5 U& s, F& d" } J4 Y: F
3 ~" M! x! t* x. M$ N1 ]So all numbers are the same, and math is pointless. |
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