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All Numbers Are Equal
! P1 `' |% [ z, HTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then
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a + b = t
$ A6 L2 D+ |1 m. F(a + b)(a - b) = t(a - b)
, v+ |3 `, ?' t+ [$ i8 ra^2 - b^2 = ta - tb! i/ ^+ c* ]. x" S1 b0 h( x+ f
a^2 - ta = b^2 - tb
7 j, u5 S0 H& L' {! ba^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
' s) R7 Y) s* ]" _! E(a - t/2)^2 = (b - t/2)^2
1 Q9 R4 ]0 Y- Wa - t/2 = b - t/2
$ J- a/ L) B( s5 l8 s- i) y1 G+ X5 da = b
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So all numbers are the same, and math is pointless. |
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